Question #184946

Determine the surface area generated by revolving the curve y=1/3 x³ over the interval (0,2), about the x-axis.

Expert's answer

**Solution**

If the curve y = f(x), a≤x≤b is rotated about the x-axis, then the surface area is given by

In this case f(x) = 1/3 x³, f’(x) = x^{2} ,a = 0, b = 2

Substitution y = x^{4}

**Answer**

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